3(x-4)+(x-3)=16 4(y-2)+2(x-8)=20 4y-1=13 -8y=160 (2x+5)-(3x-6)+(-4x+2)=5 3(3y+2)=4(2y+6) 4(5y+6)=12
Matematika
Andrewkeane124
Pertanyaan
3(x-4)+(x-3)=16
4(y-2)+2(x-8)=20
4y-1=13
-8y=160
(2x+5)-(3x-6)+(-4x+2)=5
3(3y+2)=4(2y+6)
4(5y+6)=12
4(y-2)+2(x-8)=20
4y-1=13
-8y=160
(2x+5)-(3x-6)+(-4x+2)=5
3(3y+2)=4(2y+6)
4(5y+6)=12
