tolong dijawabnya soalnya besok dikumpulkan.Terima Kasih

1. TR = 4/5 × 40
TR = 4 × 8
TR = 32 °R
2. Diketahui :
m1 = 230 gram
T1 = 90 C
m2 = 20 gram
T2 = 5 C
Ditanyakan : suhu akhir (TC) ?
Dijawab :
TC = (m1T1 + m2T2) / (m1 + m2)
= (230 × 90 + 20 × 5) / (230 + 20)
= (20.700 + 100) / 250
= 20.800 / 250
= 83,2 C
3 Reamur = 4/5 × 70 = 4 × 14 = 56 Reamur
Fahrenheit = 9/5 × 70 = 9 × 14 = 126 + 32 = 158 Fahrenheit
Kelvin= C + 273, 15 = 70 273,15 = 343,15 Kelvin

maaf kaloh ada yang salah