f(x)=ax+b f(-1)=2 f(2)=11 Tentukan rumus fungsinya

f(-1) = a (-1) + b,,,,, -a + b = 2 => b = 2 +a
f(2) = 2a + b,,,,, 2a + b = 11
subsitusikan...
2a + (2+a) = 11
2a + 2 + a = 11
3a + 2 = 11
a = 3

b = 2 + a
b = 2 + 3
b = 5

jadii,,, rumus fungsinya f(x) = 3x +5 :):):)