Jika 8log5=a, tentukan: A. 2log5 [tex]b.4 log( \frac{1}{5} ) [/tex] [tex]c.2 log( \sqrt{5} ) [/tex]
Matematika
afnia4
Pertanyaan
Jika 8log5=a, tentukan:
A. 2log5
[tex]b.4 log( \frac{1}{5} ) [/tex]
[tex]c.2 log( \sqrt{5} ) [/tex]
A. 2log5
[tex]b.4 log( \frac{1}{5} ) [/tex]
[tex]c.2 log( \sqrt{5} ) [/tex]
2 Jawaban
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1. Jawaban Albir16
a.
8log5 = a
2³log 5 = a
1/3 2log5 = a
2log5 = 3a
b.
4log(1/5)
2²log(5^-1)
-1/2 2log5
-1/2 3a = -3/2a
c.
2log(√5)
2log(5^1/2)
1/2 2log5
1/2 3a = 3/2a -
2. Jawaban bayusadewo
a. diketahui 8log 5= a
2^3 log 5 =a
1/3 2log 5 =3a
jadi 2log 5 = 3a
b. 4 log 1/5 = 2^2 log 5^-1 = -1/2 2log 5 = -1/2 (3a) = -3a/2
c. 2 log akar 5 =2 log 5^1/2 = 1/2. 2log 5 = 1/2 (3a) = 3a/2