Tolong dibantu kakak kakak

persamaan = ax + by =0
m = -a/b

1. 3x + 2y - 8 = 0 , titik (4,-3)
m= -a/b = -3/2
y-y1 = m(x-x1)
y - (-3) = -3/2(x-4)
y + 3 = -3/2x + 6 ; kedua ruas kalikan 2
2y + 6 = -3x + 12
3x + 2y = 6 atau 3x + 2y - 6 = 0

2. 3x - y + 9 = 0 , titik (2,5)
m1 = -a/b = -3/-1 = 3
tegak lurus (m2)
m1 × m2 = -1
3 × m2 = -1
m2 = -1/3
y-y1 = m(x-x1)
y - (5) = -1/3(x-2)
y - 5 = -1/3x + 2/3 ; kedua ruas kali 3
3y - 15 = -x + 2
x + 3y = 17 atau x + 3y - 17 = 0