Matematika

Pertanyaan

Xkuadrat - 6x + 11
Tolong cari rumus abc nya ya

2 Jawaban


  • [tex] {x}^{2} - 6x + 11 \\ a = 1 \: \: b = - 6 \: \: c = 11 \\ x = \frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - ( - 6) \frac{ + }{ - } \sqrt{ { - 6}^{2} - 4 \times 1 \times 11 } }{2 \times 1} \\ x = \frac{ 6 \frac{ + }{ - } \sqrt{ 36 - 44 } }{2} \\ x = \frac{ 6 \frac{ + }{ - } \sqrt{ - 8 } }{2} = \frac{ 6 \frac{ + }{ - } 2 \sqrt{ - 2 } }{2} \\ x = 3 \frac{ + }{ - } \sqrt{ - 2} \\ x1 = 3 + \sqrt{2} \: \: \: x2 = 3- \sqrt{2} [/tex]
  • a= -6x
    b= 11

    jadi -6x+11= 5

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