Matematika

Pertanyaan

Tentukan nilai dari sin 15° dan sin 75°

2 Jawaban

  • sin 15 = 0,2588190451
    sin 75 = 0,9659258263
  • sin 15° 
    = sin (45 - 30)°
    = sin 45° cos 30° - cos 45° sin 30°
    = \frac{1}{2} \sqrt{2}. \frac{1}{2} \sqrt{3}- \frac{1}{2}=​2​​1​​√​2​​​.​2​​1​​√​3​​​−​2​​1​​ 
    = \frac{1}{4} \sqrt{6}- \frac{1}{4} \sqrt{3}=​4​​1​​√​6​​​−​4​​1​​√​3​​​ 
    = \frac{1}{4}( \sqrt{6} - \sqrt{3})=​4​​1​​(√​6​​​−√​3​​​) 

    sin 75°
    = sin (30 + 45)°
    = sin 30° cos 45° + cos 30° sin 45°
    = \frac{1}{2}. \frac{1}{2} \sqrt{2}+ \frac{1}{2} \sqrt{3}. \frac{1}{2} \sqrt{2}=​2​​1​​.​2​​1​​√​2​​​+​2​​1​​√​3​​​.​2​​1​​√​2​​​ 
    = \frac{1}{4} \sqrt{2}+ \frac{1}{4} \sqrt{6}=​4​​1​​√​2​​​+​4​​1​​√​6​​​ 
    = \frac{1}{4}( \sqrt{2}+ \sqrt{6)}=​4​​1​​(√​2​​​+√​6)​​​ 

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