tentukan persamaan garis yang melalui titik (0, -9) dan bergradien a. 7 b. -5/6 c. 0 d. 6 2/3 tolong yaa pake cara makasi

a) y - y1 = m ( x - x1 )
y + 9 = 7 ( x - 0)
y = 7x - 9

b) y - y1 = m ( x - x1 )
y + 9 = - 5/6 ( x - 0)
y = - 5/6 x - 9 ( dikali 6)
6y = - 5x - 54
6y + 5x = - 54

c) y - y1 = m ( x - x1 )
y + 9 = 0 ( x - 0)
y + 9 = 0
y = - 9

d) y - y1 = m ( x - x1 )
y + 9 = 6 ⅔ ( x - 0)
y = 20/3 x - 9 ( dikali 3)
3y = 20x - 27

a. pg melalui titik (0,-9) dgn gradien 7

y-y1=m(x-x1)
y-(-9)=7(x-0)
y+9=7x
y=7x-9

b. pg melalui titik (0,-9) dgn gradien -5/6
y-y1=m(x-x1)
y-(-9)=-5/6(x-0)
y+9=-5/6x
y=-5/6x-9

c. pg melalui titik (0,-9) dgn gradien 0
y-y1=m(x-x1)
y-(-9)=0(x-0)
y+9=x
y=x-9

d. pg melalui titik (0,-9) dgn gradien 6 2/3
y-y1=m(x-x1)
y-(-9)=6 2/3(x-0)
y+9=6 2/3x
y=6 2/3x-9


maaf kalau salah