Persamaan garis yang melalui titik (1,2) dan tegak lurus garis 3x+4y=8 adalah..

m1 = -a/b
m1 = -¾
m1 × m2 = -1
-¾ × m2 = -1
m2 = -1/-¾
m2 = -1 × -4/3
m2 = 4/3
y - y1 = m(x - x1)
y - 2 = 4/3(x - 1)
3(y - 2) = 4(x - 1)
3y - 6 = 4x - 4
3y - 4x = -4 + 6
3y - 4x = 2 atau
3y - 4x - 2 = 0