tentukan persamaan garis yg melalui titik (2,5) dan tegak lurus dengan garis berikut;b. y=-1/2x +6.c.3x=-4y + 5

b. y = -½x + 6
m1 = -½
m1 × m2 = -1
-½ × m2 = -1
m2 = -1/-½
m2 = -1 × -2/1
m2 = 2
y - y1 = m(x - x1)
y - 5 = 2(x - 2)
y - 5 = 2x - 4
y - 2x = -4 + 5
y - 2x = 1 atau
y - 2x - 1 = 0
c. 3x = -4y + 5
3x + 4y = 5
m1 = -a/b
m1 = -¾
m1 × m2 = -1
-¾ × m2 = -1
m2 = -1/-¾
m2 = -1 × -4/3
m2 = 4/3
y - y1 = m(x - x1)
y - 5 = 4/3(x - 2)
3(y - 5) = 4(x - 2)
3y - 15 = 4x - 8
3y - 4x = -8 + 15
3y - 4x = 7 atau
3y - 4x - 7 = 0