nilai x yang memenuhi persamaan 5log (x-2) + 5log (2x+1) =2

5'log (x - 2) + 5'log (2x + 1) = 2
5'log (x - 2)(2x + 1) = 2
(x - 2)(2x + 1) = 5²
2x² - 3x - 27 = 0
(2x - 9)(x + 3) = 0
x = 9/2 atau x = -3

Nilai x yg memenuhi :
x = 9/2

#kutil_oh_kutil :)

5log(x-2) + 5log(2x+1) = 2
=> 5log(x-2)(2x+1) = 2
=> (x-2)(2x+1) = 25
=> 2x^2 + 3x -27 = 0
=> (2x+9)(x-3) = 0
maka x = -9/2 atau x = 3

saya harap kamu mengerti