Matematika

Pertanyaan

diketahui sistem persamaan linear
3x-y+z=10
2x+3y-z=8
x+y-2z=-10
nilai (1/x+1/y+1/z)
a.1/8
b.1/4
c.5/8
d.3/4
e.7/8

1 Jawaban

  • 3x - y + z = 10
    2x + 3y - z = 8
    ----------------------(+)
    5x + 2y = 18 ... pers 1

    3x - y + z = 10 |×2
    x + y - 2z = - 10
    maka
    6x - 2y + 2z = 20
    x + y - 2z = - 10
    -------------------------(+)
    7x - y = 10 ... pers 2

    pers 1 & 2
    5x + 2y = 18
    7x - y = 10 |×2
    maka
    5x + 2y = 18
    14x - 2y = 20
    --------------------(+)
    19x = 38
    x = 2

    subtitusi
    5x + 2y = 18
    5(2) + 2y = 18
    10 + 2y = 18
    2y = 18 - 10
    2y = 8
    y = 4

    subtitusi
    3x - y + z = 10
    3(2) - 4 + z = 10
    6 - 4 + z = 10
    2 + z = 10
    z = 10 - 2
    z = 8

    nilai 1/x + 1/y + 1/z
    = 1/2 + 1/4 + 1/8
    = 4/8 + 2/8 + 1/8
    = 7/8 ( E )

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